AquaNerd5706
18.02.2020 •
Chemistry
A solution of benzene and toluene at 25 °C exerts a total vapor pressure of 66.6 torr. What is the mole fraction of benzene in the vapor phase? The vapor pressures of pure benzene and toluene at 25 °C are 94.2 torr and 28.4 torr, respectively. 0
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Ответ:
0.5805.
Explanation:
Using Raoult's Law;
Psol = Xbenzene * P°benzene + Xtoluene * P°toluene
where,
Psol = vapor pressure of the solution
Xbenzene = mole fraction of benzene
P°benzene = vapor pressure of pure benzene
Xtoluene = mole fraction of toluene
P°toluene = vapor pressure of pure toluene
Mole fraction is defined as the ratio between the number of moles of a component in a solution to the total number of moles in the solution.
Xbenzene + Xtoluene = 1
Let,
Y = mole fraction of toluene
X = mole fraction of benzene
X = 1 − Y
Psol = X * P°benzene + (1 − X) * P°toluene
66.6 = X * 94.2 + (1 − X) * 28.4
X = 0.5805
Therefore,
Y = 1 - 0.5805
= 0.4195
Mole fraction of benzene = 0.5805.
Ответ: