kathrynway2715
08.12.2019 •
Chemistry
A1.750-g sample of mercury metal ws combined with 1.394 g of bromine. determine the empirical formula of the mercury bromide that is produced
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Ответ:
HgBr₂.
Explanation:
To determine the empirical formula of the mercury bromide that is produced, we should calculate the no. of moles of Hg (1.750 g) and Br (1.394 g) used to prepare the mercury bromide.no. of moles of Hg = mass/atomic mass = (1.75 g)/(200.59 g/mol) = 0.00872 mol.
no. of moles of Br = mass/atomic mass = (1.394 g)/(79.904 g/mol) = 0.01744 mol.
We divide by the lowest no. of moles (0.00872) to get the mole ratio:The mole ratio of (Br: Hg) is: (2: 1).
So, the empirical formula is: HgBr₂.
Ответ:
Answer is: [B] storage of radioactive waste.
Nuclear (radioactive) waste is hazardous to all forms of life and the environment.
Long term storage of radioactive waste is needed. It is important the stabilization of the waste into a form which will neither react nor degrade over many years.
If nuclear waste is wasted in atmosphere or into oceans and lagre lakes, eventually it will come in contact with living organisms.
Nuclear fission is a nuclear reaction or a radioactive decay where nucleus of atom split into smaller ligher nuclei.