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heysonic91
26.11.2019 •
Chemistry
A110 g copper bowl contains 240 g of water, both at 21.0°c. a very hot 410 g copper cylinder is dropped into the water, causing the water to boil, with 8.60 g being converted to steam. the final temperature of the system is 100°c. neglect energy transfers with the environment. (a) how much energy is transferred to the water as heat
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Ответ:
There is 98.76 kJ energy transfered to the water as heat.
Explanation:
Step 1: Data given
Mass of copper bowl = 110 grams
Mass of water = 240 grams
Temperature of water and copper = 21.0 °C
Mass of the hot copper cylinder = 410 grams
8.6 grams being converted to steam
Final temperature = 100 °C
Step 2: Calculate the energy gained by the water:
Q = m(water)*C(water)*ΔT + m(vapor)*Lw
⇒with mass of water = 0.240 kg
⇒ with C(water) = the heat capacity of water = 4184 J/kg°C
⇒ with ΔT = the change in temperature = T2 - T1 = 100 °C - 21.0 = 79°C
⇒ with mass of vapor = 8.60 grams = 0.0086 kg
⇒ with Lw = The latent heat of vaporization (water to steam) = 22.6 *10^5 J/kg
Q = 0.24kg * 4184 J/kg°C *79°C + 0.0086 kg*22.6*10^5 J/kg
Q = 79328.64 + 19436 = 98764.64 J = 98.76 kJ
There is 98.76 kJ energy transfered to the water as heat.
Ответ: