A6.0 l container holds a sample of hydrogen gas at 150 kpa. if the pressure increases to 2 atm and the temperature remains constant, what will the volume be?
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Ответ:
The volume will be 4.44 L
Explanation:
Data:
First volume, V1 = 6 L
First pressure, P1 = 150 kPa -> 150 kPa * 1 atm/101.325 kPa = 1.48 atm
Second pressure, P2 = 2 atm
Second volume, V2 = ? L
From Boyle's law:
P1*V1 =P2*V2
V2 = P1*V1/P2
V2 = 1.48*6/2
V2 = 4.44 L
Ответ:
4 atoms is the answer. I hope it helped you.
Explanation: