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delphinelilly2846
19.09.2019 •
Chemistry
After 11.5 days, 12.5% of a sample of radon-222 that originally weighed 42g remains. what is the half-life of this isotope?
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Ответ:
Nt=N0(1/2)
Ответ:
Molality is 16.1 m
Explanation:
37 % by mass indicates that 37 g of HCl, our solute, is contained in 100 g of solution. Let's determine the mass of solvent.
Mass of solution = Mass of solute + Mass of solvent
100 g = 37 g + Mass of solvent
Mass of solvent is 63 g
Let's convert the mass to kg → 63 g . 1kg / 1000 g = 0.063kg for molality
Let's convert the mass of solute to moles → 37 g . 1 mol / 36.45 g = 1.01 moles of solute
Molality → mol/kg = 1.01 mol / 0.063 kg → 16.1 m