lordcaos066
15.11.2019 •
Chemistry
Ahydrated form of copper(ii) sulfate, cuso4·nh2o(s), is heated to drive off all the waters of hydration. if we start with 9.40 grams of hydrated salt and have 5.25 grams of anhydrous cuso4(s) after heating, find the number of water molecules, n, as- sociated with each cuso4 formula unit.
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Ответ:
The hydrated form of copper(II) sulfate = CuSO4*7H2O
Explanation:
Step 1: Data given
Mass of CuSO4·nH2O(s) = 9.40 grams
After heating, 5.25 grams of anhydrous CuSO4(s)
Step 2: Calculate mass of water
Mass of CuSO4·nH2O(s) - mass of anhydrous CuSO4(s) = mass of water
9.40 grams - 5.25 grams = 4.15 grams
Step 3: Calculate moles H2O
moles = mass/ Molar mass
moles = 4.15 grams / 18.02 g/mol
moles H2O = 0.23 moles
Step 4: Calculate moles CuSO4
Moles = 5.25 grams / 159.61 g/mol
Moles = 0.0329 moles
Step 5: Calculate number of water molecules
moles H2O / moles CuSO4 = 0.23/ 0.0329 = 7
1 mol of CuSO 4 combines with 7 mol of H2O
The hydrated form of copper(II) sulfate = CuSO4*7H2O
Ответ:
Desertification
Explanation:
"The loss of trees and other vegetation can cause climate change, desertification, soil erosion, fewer crops, flooding, increased greenhouse gases in the atmosphere, and a host of problems for indigenous people."