An sample of water with a mass of 123.00 kg is heated from 25 c to 97 c. if the specific heat of water is 1 j-1 kg k-1 then how much energy is required?
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Ответ:
The amount of energy required will be 8856 Joules.
Explanation:
To calculate the amount of heat absorbed, we use the equation:
where,
Q = heat absorbed or released
m = Mass of the substance = 123 kg
c = specific heat capacity of water =![1J/kg.K](/tpl/images/0078/6433/3593d.png)
Putting values in above equation, we get:
Hence, the amount of energy required will be 8856 Joules.
Ответ:
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