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briannianoel876
17.04.2021 •
Chemistry
Answer the following question: Ethanol, C2H5OH, is considered clean fuel because it burns in oxygen to produce carbon dioxide and water with few trace pollutants. If 500.0 g of H2O are produced during the combustion of ethanol, how many grams of ethanol were present at the beginning of the reaction? When answering this question include the following:
-Have both the unbalanced and balanced chemical equations.
-Explain how to find the molar mass of the compounds.
-Explain how the balanced chemical equation is used to find the ratio of moles (hint: step 3 in the video).
-Explain how many significant figures your answer needs to have.
The numerical answer
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Ответ:
127.88 grams of ethanol were present at the beginning of the reaction
Explanation:
Firstly, let's make the combustion reaction:
C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O
By 1 mol of ethanol, you can make 3 moles of water.
A Mole of water = Water mass / Molar mass
150g / 18g/m = 8.3 mole
3 mole of water came from 1 mol of ethanol
8.3 mole came from (8.3 .1)/3 = 2.78 mole of ethanol
Molar mass ethanol = 46 g/m
Mole . molar mass = mass
2.78 m . 46g/m = 127.88 g
Ответ:
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Explanation:
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