Chemistry: Arrange the following aqueous solutions in order of increasing boiling points 0.050 m mg(no3): 0.100 m ethanol 0.090 m nacl ethanol

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Arrange the following aqueous solutions in order of

mariap3504

02.01.2022

The order of increasing boiling points follows:

$\text{Ethanol }$

Explanation:

The expression of elevation in boiling point is given as:

$\Delta T_b=i\times k_b\times m$

where,

$\Delta T_b$ = Elevation in boiling point

i = Van't Hoff factor

T_b = change in boiling point

k_b = boiling point constant

m = molality

For the given options:

Option 1: 0.050 m Mg(NO_3)_2

Value of i = 3

So, molal concentration will be = $(0.05)\times 3=0.15m$

Option 2: 0.100 m ethanol

Value of i = 1 (for non-electrolytes)

So, molal concentration will be = $(0.100)\times 1=0.100m$

Option 3: 0.090 m NaCl

Value of i = 2

So, molal concentration will be = $(0.09)\times 2=0.18m$

As, the molal concentration of NaCl is the highest, so its boiling point will be the highest.

Thus, the order of increasing boiling points follows:

$\text{Ethanol }$

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