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andrew2786
02.12.2019 •
Chemistry
Asample of 30.00 grams of potassium phosphate was added to a solution containing 100.0 ml of 0.25 m calcium nitrate. calcium phosphate was precipitated according to the following reaction. 2k3po4(s) + 3ca(no3)2(aq) - ca3(po4)2(s) + 6kno3(aq) 2.25 grams of calcium phosphate were recovered. calculate the theoretical yield and the percent yield.
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Ответ:
Theoretical yield of Ca₃(PO₄)₂ = 19.67 g
Percent yield of Ca₃(PO₄)₂ = 11.4 %
Explanation:
Data given
Potassium Phosphate K₃PO₄ = 30.00 g
calcium nitrate Ca(NO₃)₂ of 0.25 M = 100.0 mL
Reaction given:
2K₃PO₄(s) + 3Ca(NO₃)₂(aq) > Ca₃(PO₄)₂(s) + 6KNO₃(aq)
Solution :
Part A :
To find the theoretical yield of Calcium phosphate
Look at the reaction :
2K₃PO₄(s) + 3Ca(NO₃)₂(aq) > Ca₃(PO₄)₂(s) + 6KNO₃(aq)
2 mol 3 mol 1 mol 6mol
So,
2 mol of 2K₃PO₄ give 1 mole of Ca₃(PO₄)₂
if we represent mole in mass then
Molar Mass of K₃PO₄ = 3(39) + 31 + 4(16)
Molar Mass of K₃PO₄ = 212 g/mol
and
Molar mass of Ca₃(PO₄)₂ = [ 3(40) + 2((31) + 4(16))]
Molar mass of Ca₃(PO₄)₂ = [ 120 + 62 + 96] = 278 g/mol
Molar mass of Ca₃(PO₄)₂ = 278 g/mol
Now, if we write it in grams
2K₃PO₄(s) + 3Ca(NO₃)₂(aq) > Ca₃(PO₄)₂(s) + 6KNO₃(aq)
2 mol 3 mol 1 mol 6mol
2 mol ( 212 g/mol) 1 mol (278 g/mol)
424 g 278 g
So from the above information we come to know that
424 g of K₃PO₄ gives 278 g of Ca₃(PO₄)₂
then 30 g will give how much Ca₃(PO₄)₂ Calcium phosphate
Apply unity formula
424 g of K₃PO₄ ≅ 278 g of Ca₃(PO₄)₂
30 g of K₃PO₄ ≅ x g of Ca₃(PO₄)₂
By doing cross multiplication and rearranging the above values
x g of Ca₃(PO₄)₂ = 278 g x 30 g / 424 g
x g of Ca₃(PO₄)₂ = 19.67 g
So,
30 g of K₃PO₄ will give 19.67 g Ca₃(PO₄)₂ theoretically.
Theoretical yield of Ca₃(PO₄)₂ = 19.67 g
Now,
Part B :
To find percent yield of Ca₃(PO₄)₂
Solution
Data given:
Actual yield of Ca₃(PO₄)₂ = 2.25 g
Theoretical yield of Ca₃(PO₄)₂ = 19.67 g
Formula to be used:
Percentage yield = Actual yield/ theoretical yield x 100 %
Put values in Above formula
Percent yield = 2.25 g / 19.67 g x 100 %
Percent yield = 0.1144 / 100 %
Percent yield = 11.4 %
So,
Percent yield of Ca₃(PO₄)₂ = 11.4 %
Ответ:
Explanation:
the equation must be
4NH3 + 5O2–> 4NO + 6H2O