Balance the following equation by adding the correct mole numbers.
P⁴+Cl²->PCl³

Hey there!

P₄ + Cl₂ → PCl₃

First, let's balance Cl.

There are 2 on the left, and 3 on the right.

To balance this, let's put a coefficient of 3 in front of Cl₂ and a coefficient of 2 in front of PCl₃.

P₄ + 3Cl₂ → 2PCl₃

Now we have 6 on the left and 6 on the right.

Next, let's balance P.

There are 4 on the left and 2 on the right.

Let's change the coefficient in front of PCl₃ from 2 to 4.

P₄ + 3Cl₂ → 4PCl₃

There are now 4 P on each side.

However, now Cl is unbalanced, with 6 on the left and 12 on the right.

We can change the coefficient in front of Cl₂ from 3 to 6.

P₄ + 6Cl₂ → 4PCl₃

So now, we have 4 P on each side and 12 C on each side.

This is our final balanced equation.

Hope this helps!