Chemistry: Bone cells are found in what kind of tissue the anwser choices are muscle connective nerve epithelial

Answer : The percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.Explanation :First we have to calculate the number of atoms in 5.5 wt% Pb and 94.5 wt% of Sn.As, 207.2 g of lead contains atomsSo, 5.5 g of lead contains atomsand,As, 118.71 g of lead contains atomsSo, 94.5 g of lead contains atomsNow we have to calculate the percent composition of Pb and Sn in atom.and,Thus, the percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively....

Bone cells are found in what kind of tissue the

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singlegirlforlife541

25.12.2022

Chemistry

Answer : The percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

Explanation :

First we have to calculate the number of atoms in 5.5 wt% Pb and 94.5 wt% of Sn.

As, 207.2 g of lead contains $6.022\times 10^{23}$ atoms

So, 5.5 g of lead contains $\frac{5.5}{207.2}\times 6.022\times 10^{23}=1.59\times 10^{22}$ atoms

and,

As, 118.71 g of lead contains $6.022\times 10^{23}$ atoms

So, 94.5 g of lead contains $\frac{94.5}{118.71}\times 6.022\times 10^{23}=4.79\times 10^{23}$ atoms

Now we have to calculate the percent composition of Pb and Sn in atom.

$\% \text{Composition of Pb}=\frac{\text{Atoms of Pb}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100$

$\% \text{Composition of Pb}=\frac{1.59\times 10^{22}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=3.21\%$

and,

$\% \text{Composition of Sn}=\frac{\text{Atoms of Sn}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100$

$\% \text{Composition of Sn}=\frac{4.79\times 10^{23}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=96.8\%$

Thus, the percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

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Bone cells are found in what kind of tissue the anwser choices are muscle connective nerve epithelial

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