Burning one mole of propane according to the following reaction liberates 526 kcal of energy. If all of the coefficients are tripled, how much energy will be released? C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(I)

%(Zn) = 67%

%(S) = 33%

Explanation:

Step 1: Given data

Step 2: Calculate the mass of the compound

The mass of the compound is equal to the sum of the masses of the elements that form it.

mCompound = mZn + mS = 32 g + 16 g = 48 g

Step 3: Calculate the percent composition of each element in the compound

We will use the following expression.

%(Element) = mElement / mCompound × 100%

%(Zn) = 32 g / 48 g × 100% = 67%

%(S) = 16 g / 48 g × 100% = 33%