foreignking02
05.05.2020 •
Chemistry
Calculate the equilibrium constant for the decomposition of water 2h2o(l) 2h2(g) + o2(g) at 25°c, given that g°f (h2o(l)) = –237.2 kj/mol.
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Ответ:
2.6 ×10^-42
Explanation:
From
∆G= -RTlnK
∆G= -237.2 KJmol-1 or -237.2×10^3 Jmol-1
R= 8.314 Jmol-1K-1
T= 25°C + 273= 298K
-237.2×10^3= 8.314 × 298 × ln K
ln K= -237.2×10^3/2477.572
K = 2.6 ×10^-42
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A. A but give brainliest to them
Explanation: