Chemistry: Calculate the mass (in grams) of 7.66×1019 CCl2F2 molecules

Calcular la molalidad de la siguiente disolución: 10,5 g de benceno C6H6 disuelto en 18,5 g de tetracloruro de carbono (CCl4)7,27 m...

Calculate the mass (in grams) of 7.66×1019 CCl2F2 - id76610192214404948, israelduran2222

Isabelcastillox1085

22.09.2021

$\footnotesize\implies Number \: of \: moles = \dfrac{Molecules}{Avogadro's \: number}$

$\footnotesize\implies Number \: of \: moles = \dfrac{Given \: mass}{Gram \: molecular \: mass}$

Equate both the equations:

$\footnotesize\implies \dfrac{Molecules}{Avogadro's \: number} = \dfrac{Given \: mass}{Gram \: molecular \: mass}$

Gram molecular mass of the given compund:

$\footnotesize\implies CCl_2F_2 =12 + 35.5 \times 2 + 18 \times 2$

$\footnotesize\implies CCl_2F_2 =12 + 71 + 36$

$\footnotesize\implies CCl_2F_2 =119 \: g$

Now, substitue the known values in the given formula:

$\footnotesize\implies \dfrac{Molecules}{Avogadro's \: number} = \dfrac{Given \: mass}{Gram \: molecular \: mass}$

• Molecules = 7.66×10¹⁹

• Avogadro's number = 6.022 × 10²³

• Gram molecular mass = 119 g

• Mass = ?

$\footnotesize\implies \dfrac{7.66 \times {10}^{19} }{6.022 \times {10}^{23} } = \dfrac{Given \: mass}{119}$

$\footnotesize\implies \dfrac{7.66 \times {10}^{19} \times {10}^{ - 23} }{6.022 } = \dfrac{Given \: mass}{119}$

$\footnotesize\implies 1.272 \times {10}^{ -4} = \dfrac{Given \: mass}{119}$

$\footnotesize\implies Given \: mass = 1.272 \times {10}^{ -4} \times 119 \\$

$\footnotesize\implies Given \: mass =151.368 \times {10}^{ - 4}$

$\footnotesize\implies Given \: mass =1.51368 \times {10}^{ - 2} \times {10}^{ - 4}$

$\footnotesize\implies \bf Given \: mass =1.51368 \times {10}^{ - 6} \: g \:mol$

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