tytybruce2
25.02.2020 •
Chemistry
Calculate the percent ionization of propionic acid (C2H5COOH) in solutions of each of the following concentrations (Ka is given in Appendix D in the textbook).
Part A. 0.270 M
Part B. 7.84×10-2 M
Part C. 1.97×10-2 M
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Ответ:
a) = 0.704%
b) = 1.30%
c) = 2.60%
Explanation:
Given that:
=
For Part A; where Concentration of A = 0.270 M
Percentage Ionization(∝)
percentage% (∝) =
= 0.704%
For Part B; where Concentration of B = M
percentage% (∝) = 0.0130 × 100%
= 1.30%
For Part C; where Concentration of C=
percentage% (∝) = 0.02608 × 100%
= 2.60%
Ответ:
Combination reaction