Chemistry: Calculate the pH of a [0.000765) M solution of KOH

As we know the formula for density is .. Density = Mass/ Volume So therefore putting in the values we get.. D=2.40/2.68 D= 0.89 kg/l...

Calculate the pH of a [0.000765) M solution of - id00007656539655, crickel40pa8sxe

Ответ:

cairolove228

27.01.2022

Chemistry

pH=10.88

Explanation:

Hello,

In this case, since potassium hydroxide is completely dissociated as shown below:

$KOH\rightarrow K^++OH^-$

For which we understand it is a base, more specifically, a strong base; it means that the concentration of the OH⁻ equals the concentration of the potassium hydroxide, that is 0.000765M, for that reason we can directly compute the pOH:

pOH=-log([OH^-])=-log(0.000765)=3.12

Finally, since the pOH and the pH are related by:

pOH+pH=14

The pH turns out:

$pH=14-3.12\\pH=10.88$

Best regards.

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Calculate the pH of a [0.000765) M solution of KOH

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