Calculate the vapor pressure of a solution containing 27.2 g of glycerin (c3h8o3) in 132 ml of water at 30.0 ? c. the vapor pressure of pure water at this temperature is 31.8 torr. assume that glycerin is not volatile and dissolves molecularly (i.e., it is not ionic) and use a density of 1.00 g/ml for the water.
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Ответ:
Roult's Law states that the vapor pressure, p, of a solution of a non-volatile solute is equal to the vapor pressure of the pure solvent, Po solv, times the mole fraction of the solvent, Xsolv
p = Xsolv * Po sol
X solv = number of moles of solvent / number of moles of solution
The solvent is water and the solute (not volatile) is glycerin.
Number of moles = mass in grams / molar mass
mass of water = 132 ml * 1 g/ml = 132 g
molar mass of water = 18 g/mol
=> number of moles of water = 132 g / 18 g/mol = 7.33333 mol
mass of glycerin = 27.2 g
molar mass of glycerin:, C3H8O3: 3 * 12 g/mol + 8 * 1 g/mol + 3*16 g/mol = 92 g/mol
number of moles of glycerin = 27.2g / 92 g/mol = 0.29565
total number of moles = 7.33333 moles + 0.29565 moles = 7.62898 moles
=> X solv = 7.33333 / 7.62898 = 0.96125
=> p = 0.96125 * 31.8 torr ≈ 30.57 torr ≈ 30.6 torr.
30.6 torr
Ответ:
Carbon disulfide (CS2).
Explanation:
Carbon + sulfur = Carbon disulfide (CS2).