Chemistry: Compute the electrical conductivity of cylindrical silicon specimen 5.1 mm (0.2 in.) in diameter and 51 mm (2 in.) in length in which a current of 0.1 A passes in an axial direction. A voltage of 12.5 V is measured across two probes that are separated by 38 mm (1.5 in.).

The correct answer is: Mutual FundExplanation:...

Compute the electrical conductivity of cylindrical

Thnut4237

18.01.2022

Therefore electric conductivity $\sigma$ =1.46 (Ω-m)⁻¹

Explanation:

$\sigma=\frac{1}{\rho} =\frac{Il}{VA}$

Here σ= electrical conductivity

= current = 0.1 A

= length= 38 mm= 38×10⁻³ m

v= voltage = 12.5 V

A = area = $\pi(\frac{d}{2} )^{2}$ = $\pi (\frac{51\times 10^{-3}}{2} )^2$ m²

$\sigma=\frac{(0.1)\times 38\times 10^{-3}}{12.5\times \pi (\frac{51\times 10^{-3}}{2} )^2 }$

=1.46 (Ω-m)⁻¹

Therefore electric conductivity $\sigma$ =1.46 (Ω-m)⁻¹

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