ashhleyjohnson
10.10.2019 •
Chemistry
Consider the reaction: so2cl2(g)⇌so2(g)+cl2(g) kp=2.91×103 at 298 k in a reaction at equilibrium, the partial pressure of so2 is 0.156 atm and that of cl2 is 0.370 atm . part a what is the partial pressure of so2cl2 in this mixture?
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Ответ:
1.98 x 10⁻⁵ atm.
Explanation:
For the reaction: SO₂Cl₂(g) ⇌ SO₂(g) + Cl₂(g), Kp = 2.91 x 10³.∵ Kp = (PSO₂)(PCl₂)/(PSO₂Cl₂).
PSO₂ = 0.156 atm, PCl₂ = 0.370 atm.
∴ 2.91 x 10³ = (0.156 atm)(0.370 atm)/(PSO₂Cl₂)
∴ (PSO₂Cl₂) = (0.156 atm)(0.370 atm)/(2.91 x 10³) = 1.98 x 10⁻⁵ atm.
Ответ:
2- u answered
3-c
4-d
5- u answered
6-c
7-c but i’m not sure