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carapiasebas
07.07.2019 •
Chemistry
Describe how you would prepare 350 ml of 0.100 m c12h22o11 starting with 3.00l of 1.50 m c12h22o11
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Ответ:
To prepare 350 mL of 0.100 M solution from a 1.50 M solution, we simply have to use the formula:
M1 V1 = M2 V2
So from the formula, we will know how much volume of the 1.50 M we actually need.
1.50 M * V1 = 0.100 M * 350 mL
V1 = 23.33 mL
So we need 23.33 mL of the 1.50 M solution. We dilute it with water to a volume of 350 mL. So water needed is:
350 mL – 23.33 mL = 326.67 mL water
Steps:
1. Take 23.33 mL of 1.50 M solution
2. Add 326.67 mL of water to make 350 mL of 0.100 M solution
Ответ:
Due to boiling of ethanol. it was in the atmosphere and contaminate with other solution.