Determine the mass in grams of 7.354 moles of ba3(po4)2? explain all your work

Find the molar mass of each element: (To do this, find the atomic weight of the element and multiply it by the subscripts, or is some cases, the coefficient)

Ba3 - 137.327 X 3 = 412 (rounded)

P2 - 30.97 X 2 = 61.94

O8 - 16 X 8 = 128

Add these up, and you have the molar mass of 601.94

Set your equation up:

7.354M of Ba3(PO4)2  X 601.94g / 1 mole of Ba3(PO4)2

(It will be much easier to see the units cancel out if you write this equation on paper)

The moles cancel out, and you are left with the unit of grams.

4426 (rounded)