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burntquesadilla
10.09.2019 •
Chemistry
Determine the mass of chloride (mw = 35.45 g/mol ) in grams present in 100 ml of a 0.273 m solution of aqueous fecl₃ (iron(iii) chloride). express the mass in grams to three significant figures.
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Ответ:
The mass chloride is 2.903 grams
Explanation:
Step1: calculate the moles of FeCl3
moles = molarity x volume in liters
volume in liters = 100 ml /1000 = 0.1 L
molarity = 0.273 M = 0.273 mol / L
moles = 0.273 mol /L x 0.1 L = 0.0273 moles
step 2: find the moles of Cl
since there is 3 atoms of cl in FeCl3
= 3 x 0.0273 =0.0819 moles
Step 3: calculate mass of cl
mass= moles x molar mass
=0.0819 moles x 35.45 g/mol = 2.903 g
Ответ:
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