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adrian08022
28.08.2019 •
Chemistry
Discuss your thoughts on the overall lab design. did it you understand the concepts better, or did it raise more questions?
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Ответ:
-1.37 kJ/mol
Explanation:
The expression for the calculation of the enthalpy of dissolution of [tex[NH_4NO_3[/tex] is shown below as:-
Where,
m is the mass
C is the specific heat capacity
Thus, given that:-
Mass of ammonium nitrate = 5.60 g
Specific heat = 4.18 J/g°C
So,
Negative sign signifies loss of heat.
Also, 1 J = 0.001 kJ
So,
Also,
Molar mass of [tex[NH_4NO_3[/tex] = 80.043 g/mol
The formula for the calculation of moles is shown below:
Thus,
Thus,![\Delta H=-\frac{0.096}{0.06996}\ kJ/mol=-1.37\ kJ/mol](/tpl/images/0421/9473/bbeec.png)