Exactly one mole of an ideal gas is contained in a 2.00-liter container at 1,000 k. what is the pressure exerted by this gas?
given: r = 0.08205 l · atm/k · mol
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Ответ:
so P = nRT/V
= 1 mole(0.08205 L atm/K mol)(1000K) / 2 L
= 41 atm
Ответ: