find the temperature (°c) of 1.25 moles of a gas if the gas has a volume 20.0 liters at a pressure of
1.75 atm.
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Ответ:
T = 66.66 °C
Explanation:
Given data:
Moles of gas = 1.25 mol
Volume of gas = 20.0 L
Pressure of gas = 1.75 atm.
Temperature of gas = ?
Solution:
PV= nRT
T = PV/ nR
T = 1.75 atm × 20 L / 1.25 mol ×0.0821 atm. L. mol⁻¹ . K⁻¹
T = 35 atm. L / 0.103 atm. L. K⁻¹
T = 339.81 K
T = 339.81 K - 273.15 = 66.66 °C
Ответ: