Find the volume needed to prepare a 0.694 m pb(no3)2 solution if you start with 110 g of pb(no3)2
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Ответ:
0.479 dm^3 (or 479 cm^3)
Explanation:
First, calculate the no. of moles in 110g of Pb(NO3)2.
According to the periodic table, molar mass of Pb is 207.2, N is 14,0, O is 16.0
so, the molar mass of Pb(NO3)2 = 207.2 + (14.0 + 16.0 x 3) x 2 = 331.2
With the formula:
no. of moles = mass/molar mass
no. of moles in 110g of Pb(NO3)2 = 110 / 331.2
= 0.33213 mol
Then, with the formula:
molarity = no. of moles / volume
0.694 = 0.33213 / v
v = 0.479 dm^3 (or 479 cm^3)
Therefore, the volume needed is 0.479 dm^3 (or 479 cm^3)
Ответ:
5.4 days (6 days)
Step-by-step explanation:
First set up an equation. (x represents days)
5 dollars a day = 5x ; Already has 45 = +45 ; Needs 72 = =72
That means your equation is...
5x + 45 = 72
Now solve for x.
5x = 27 Subtract 45 from both sides.
x = 5.4 Divide both sides by 5.
This means he will have to work for at least 6 days.
I hope this helped. :) (I love these kinds of problems!)