Flouride is known to prevent tooth decay so it is added to the city water supply for drinking. a medium sized city is populated with 150,000 people. each person uses approximately 660.0 l of water each day. how many kg of naf must be added to the water supply each year to have the required flouride concentration of 1.0 ppm?
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Ответ:
3.6 × 10^4 kg NaF
Step 1. Calculate the daily volume of water used
Volume = 150 000 persons × (660.0 L/1 person) = 9.90 × 10^7 L
Step 2. Calculate the daily mass of the water
Mass of water = 9.90 × 10^7 L water× (1.00 kg water water/1 L water)
= 9.90 × 10^7 kg water
Step 3. Calculate the daily mass of NaF
Daily mass of NaF = 9.90 × 10^7 kg water × (1.0 kg NaF/10^6 kg water)
= 99.0 kg NaF
Step 4. Calculate the yearly mass of NaF
Yearly mass of NaF = (99.0 kg NaF/1 day) × (365.25 days/1 yr)
= 3.6 × 10^4 kg NaF
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