Chemistry: Formal charge of hcooh

Formal charge of hcooh - id9123181, kdog1738

emelylug033

15.04.2021

236 cubic cm

Explanation:

We are given that

Initial volume, V1=200 cubic centimeter

Initial temperature, T1=60 degree Celsius=60+273=333 K

Final temperature, T2=120 degree Celsius=120+273=393 K

Kelvin temperature=Celsius temperature+273

We have to find the new volume of the balloon.

We know that

Charles's law

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

Using the formula

$\frac{200}{333}=\frac{V_2}{393}$

$V_2=\frac{200\times 393}{333}$

V_2=236cm^3

Hence, the new volume of the balloon will be 236 cubic cm.

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