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kiki197701
01.04.2020 •
Chemistry
Given the following standard reduction potentials at 25°C:
Half reaction
Ag (aq) + e → Ag (S)
Cu(ag) + 2e → Cu (S)
Ni?' (ag) + 2e → Ni (s)
Cr+ (aq) + 3e → Cr(s)
Reduction Potential (V)
+ 0.80
+0.34
- 0.28
-0.74
1. Combine these reduction half-reactions into a redox reaction (hint-one will be a
reduction, the other will be an oxidation) such that the Ecell is the smallest positive value
possible.
Balanced redox reaction:
Eceh
mV
2. What is 'n' from the reaction above? n=
moles electrons
3. What is delta G and is this reaction spontaneous or not? delta G=
4. What is K?K=
5. Is the reaction product-favored or reactant favored?
Solved
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Ответ:
3.36 L of ammonia gas
Explanation:
The balanced chemical reaction is:
According to stoichiometry :
3 moles of
produce = 2 moles of ![NH_3](/tpl/images/1210/1154/b033f.png)
Thus 0.75 moles of
will producee=
of ![NH_3](/tpl/images/1210/1154/b033f.png)
But as percent yield is 30 %, amount of ammonia produced =![\frac{30}{100}\times 0.50moles=0.15moles](/tpl/images/1210/1154/5da42.png)
According to ideal gas equation:
P = pressure = 1 atm
V = Volume = ?
n = number of moles = 0.15
R = gas constant =![0.0821Latm/Kmol](/tpl/images/1210/1154/febab.png)
T =temperature =![273K](/tpl/images/1210/1154/3d4f2.png)
Thus 3.36 L of ammonia gas is obtained by reacting 0.75 moles of hydrogen with excess nitrogen.