Given the reactant side of the total ionic equation for the neutralization reaction of sodium hydroxide (naoh) with hydrochloric acid (hcl), write the total ionic equation (also known as the complete ionic equation) by entering both the reactant and the product species, separated by the reaction arrow. na+(aq)+oh−(aq)+h+(aq)+cl−(aq)→ ? be sure to include the charges on the ionic species and the physical state of all the reactant and product species. express your answer as a chemical equation.

Just to help to understand what is happening here, I will show you the complete non ionic reaction (this is just a reference not the answer)

NaOH (aq) + HCl (aq) -> NaCl (aq) + H2O

Now, you have to separate the ionics substances into the ions, which gives the desired
 
Na+(aq)+OH−(aq)+H+(aq)+Cl−(aq)→ Na+ (aq) + Cl- (aq) + H+ (aq) + OH- (aq)

Step-by-step explanation:

P of original = 14 + 10 = 24

P of original l + 1  and w - 1 = 16 + 8 = 24

P of original l + 2  and w - 2 = 18 + 6 = 24

The perimeter remains the same each time since Perimeter is to the 1st power and you are summing; by subtracting from one and adding the same amount to another measure there is no change in perimeter

A of original = 7 x 5 = 35

A of original l + 1  and w - 1 = 8 x 4 = 32

A of original l + 2  and w - 2 = 9 x 3 = 27

A of original l + 3  and w - 3 = 10 x 2 = 20

A of original l + 4  and w - 4 = 11 x 1 = 11

The area decreases by 3,5,7,9 units each time since Area is to the 2nd power since you are multiplying two measures, now if you take the 2nd differences of 3,5,7,9 you see that they are 2 units apart each time, so are is squared and the 2nd differences are constant