Chemistry: Helium (he) is the lightest noble gas component of air, and xenon (xe) is the heaviest. perform the following calculations, using r = 8.314 j/(mol·k) and ℳ in kg/mol. (a) find the rms speed of he in winter (0.°c) and in summer (30.°c). enter your answers in scientific notation.

Helium (he) is the lightest noble gas component of

Ответ:

kakalli9999

08.01.2022

Chemistry

$\large \boxed{\text{(a) } 1.30 \times 10^{3}\text{ m/s}; \text{(b) }1.37 \times 10^{3}\text{ m/s}}$

Explanation:

$v_{\text{rms}} = \sqrt{\dfrac{3RT}{M}$

(a) Speed in winter

T = (0. + 273.15) K = 273.15 K

$v_{\text{rms}} = \sqrt{\dfrac{3\times 8.314\text{ J}\cdot\text{K}^{-1} \text{mol}^{-1} \times 273.15 \text{ K}}{4.013 \times 10^{-3} \text{ kg}\cdot \text{mol}^{-1}}}\\\\=\sqrt{1.846\times 10^{6} \text{ (m/s)}^{2}} = 1.30 \times 10^{3}\text{ m/s}\\\text{The rms speed in winter is $ \large \boxed{\mathbf{1.30 \times 10^{3}}\textbf{ m/s}}$}$

(b) Speed in summer

T = (30. + 273.15) K = 303.15 K

$v_{\text{rms}} = \sqrt{\dfrac{3\times 8.314\text{ J}\cdot\text{K}^{-1} \text{mol}^{-1} \times 303.15 \text{ K}}{4.013 \times 10^{-3} \text{ kg}\cdot \text{mol}^{-1}}}\\\\=\sqrt{1.884\times 10^{6} \text{ (m/s)}^{2}} = 1.37 \times 10^{3}\text{ m/s}\\\text{The rms speed in summer is $ \large \boxed{\mathbf{1.37 \times 10^{3}}\textbf{ m/s}}$}$

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Ответ:

jillian0013

17.09.2022

Chemistry

Answer is: potassium hydroxide (KOH).

Balanced chemical reaction: MgCl₂ + 2KOH → Mg(OH)₂ + 2KCl.

n(MgCl₂) = 6 mol; amount of magnesium chloride.

n(KOH) = 6 mol; amount of potassium hydroxide.

From balanced chemical reaction: n(MgCl₂) : n(KOH) = 1 : 2.

6 mol : n(KOH) = 1 : 2.

n(KOH) = 6 mol · 2.

n(KOH) = 12 mol; potassium hydroxide is limiting reagent, because we need 12 moles of it for chemical reaction and there is only 6 moles.

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Helium (he) is the lightest noble gas component of air, and xenon (xe) is the heaviest. perform the following calculations, using r = 8.314 j/(mol·k) and ℳ in kg/mol. (a) find the rms speed of he in winter (0.°c) and in summer (30.°c). enter your answers in scientific notation.

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