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Mole fraction  = 0.1313

Explanation:

given data

Addition rate of pure phosphoric acid = 30L/min

Phosphoric acid added in 25 min = 750 L

solution

mass is express as here

mass = density × volume and number of moles = mass ÷ molar mass

So, In terms of moles

phosphoric acid added = (750 × 1.834) ÷ 98

phosphoric acid added = 14.036 kmol

and

moles of phosphoric acid in tank = 0.05 × 150 + 14.036

moles of phosphoric acid in tank = 21.536 kmol

and

Moles of water in tank = 0.95 × 150

Moles of water in tank = 142.5 kmol

So that Mole fraction of phosphoric acid in tank

Mole fraction = 21.536 ÷ (21.536+142.5)

Mole fraction  = 0.1313