reghanhoward3
08.10.2019 •
Chemistry
How many atoms of gold are in 112 grams of gold?
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Ответ:
196.96 g 6.02x10²³ atoms
112 g ( atoms)
atoms = 112 x ( 6.02x10²³) / 196.96
atoms = 6.74x10²⁵ / 196.96
= 3.42x10²³ atoms
hope this helps!
Ответ:
The pH of resulting solution is 9.08
Explanation:
To calculate the number of moles for given molarity, we use the equation:
........(1)
For HCl:Molarity of HCl = 0.40 M
Volume of solution = 15.0 mL
Putting values in equation 1, we get:
For ammonia:Molarity of ammonia = 0.50 M
Volume of solution = 20.0 mL
Putting values in equation 1, we get:
The chemical reaction for hydrochloric acid and ammonia follows the equation:
Initial: 0.006 0.01
Final: - 0.004 0.006
Volume of solution = 15.0 + 20.0 = 35.0 mL = 0.035 L (Conversion factor: 1 L = 1000 mL)
To calculate the pOH of basic buffer, we use the equation given by Henderson Hasselbalch:We are given:
= negative logarithm of base dissociation constant of ammonia =
pOH = ?
Putting values in above equation, we get:
To calculate pH of the solution, we use the equation:
Hence, the pH of the solution is 9.08