How many grams of gas are present in a sample that has a molar mass of 70.0 g/mol and occupies a 2.00 l container at 117 kpa and 35.1 degrees celsius?
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Ответ:
PV=nRT
n = PV/RT
= (1.155 × 2)/ (0.0821 × 308.25)
= 0.0913 moles
But, 1 mole = 70 g
Therefore, 0.0913 moles × 70 = 6.39 g
Ответ: