carolynhstevens
28.01.2020 •
Chemistry
How many grams of na3aso3 is produced from the reaction of 6.90 moles of naoh?
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Ответ:
Explanation:
6.90 mol x grams
2As + 6NaOH = 2Na3AsO3 + 3H2
6 mol 2 mol
192 g/mol
6.90 mol NaOH x 2 mol Na3AsO3/6 mol NaOH== 2.3 mol Na3AsO3
2.3 mol Na3AsO3 x 192 g/mol = 442 g Na3AsO3
Ответ:
jealous
Explanation: