How many joules of energy are released when 45,0g of water coc s from 18.0°C to 7.0°C?
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Ответ:
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Ответ:
156.78 °C
Explanation:
First we convert 9.8 grams of NH₃ into moles, using its molar mass:
9.8 g ÷ 17 g/mol = 0.576 molThen we can use the PV=nRT formula to calculate the temperature, where:
P = 98.3 kPa ⇒ 98.3/101 = 0.967 atmV = 21.0 Ln = 0.576 molR = 0.082 atm·L·mol⁻¹·K⁻¹T = ?We input the data:
0.967 atm * 21.0 L = 0.576 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * TAnd solve for T:
T = 429.94 KFinally we convert 429.94 K to °C:
429.94 - 273.16 = 156.78 °C