How many molecules are there in 4.00 L of glucose, C6H1206? Please show your work!!

As 1 L is 1000 g
So mass= 4000g
Molar mass of Glucose= 180 g/mol
As Number of molecules= mass/molar mass x Avogadro’s no.
Number of molecules= 4000/180 x 6.022 x 10^23
Number of molecules = 1.3 x 10^25 molecules

Molar mass of NO2= 46
Number of molecules = 14/46 x 6.022 x 10^23
Number of molecules= 1.8 x 10^23 molecules

It decreases by about 10%

Explanation: