How many moles of carbon dioxide are produced when 22.8g of butane react

Butane undergoes combustion to produce carbon dioxide and water, expressed in the following reaction  C4H10 (g) + O2 (g) → 4CO2 (g) + 5H2O (g) . 1 mole of butane is to 4 moles of CO2. In this case, when 22.8 grams of butane or 0.393 moles of it, 69.18 grams of carbon dioxide is produced

The answer is KF.

Explanation:

Ionic bonding occurs, when a metal and a non-metal combines together to form ionic compound. In KF, K is a metal and F is a non-metal.