Chemistry: How many moles of nano3 are present in a 44.0 g sample

The answer is 535.89 ml hint: formula m1v1=m2v2...

How many moles of nano3 are present in a 44.0 g sample

ashtonfordham987

15.01.2022

Answer : The number of moles of NaNO_3 present in a given sample are 0.518 moles.

Explanation : Given,

Mass of NaNO_3 = 44.0 g

Molar mass of NaNO_3 = 84.99 g

Formula used :

$\text{Moles of }NaNO_3=\frac{\text{Mass of }NaNO_3}{\text{Molar mass of }NaNO_3}$

Now put all the given values in this formula, we get:

$\text{Moles of }NaNO_3=\frac{44.0g}{84.99g.mol}=0.518mole$

Therefore, the number of moles of NaNO_3 present in a given sample are 0.518 moles.

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