How many moles of neon gas have a volume of 0.84 L and a pressure of 4.6 atm at 222k

n = 0.21 moles

Explanation:

Given that,

Volume, V = 0.84 L

Pressure, P = 4.6 atm

T = 222 K

We need to find the number of moles of Neon gas. We know that,

PV = nRT

Where

n is the number of moles

R i the gas constant, R = 0.08206 L-atm/mol-K

Put all the values,

So, there are 0.21 moles of Neon gas.

Molar Mass of 1 molecule of methane(CH4) = 12 + 4 = 16g/mol

That is, 16g if CH4 contain 1 mole molecule of it

= 6.022×10²³ molecules of CH4 which consists of 1 mole of C atoms and 4 moles of H atoms.

= 4 g of CH4 contains 1/4 × 6.022×10²³ molecules

= 1.5055×10²³ molecules of CH4

= 1.5055×10²³ C atoms and 6.022×10²³ H atoms