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Thejollyhellhound20
12.01.2020 •
Chemistry
How much heat is required to increase the temperature of 100.0 grams of iron from 15.0oc to 40.2oc? (the specific heat of iron is 0.46 j/g xoc).
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Ответ:
specific heat= 0.46 j/g-C
mass= 100.0 grams
ΔT= 40.2 - 15.0= 25.2C
heat= (0.46) x (100.0) x (25.2)= 1159.2 joules or 1200 joules (rounded off)
Ответ:
The correct answer is -5318 KJ.
Explanation:
We calculate the reaction enthalphy (ΔHr) from formation enthalpies of reactants and products as follows:
ΔHr= ΔHfº (products) - ΔHfº (reactants)
ΔHr= (10 x ΔHfº(H₂O) + 8 x ΔHfº(CO₂)) - (2 x ΔHfº(C₂H₁₀) + 13 x ΔHfº(O₂))
As the formation enthalphy of an element in its standard state is zero⇒ ΔHfº(O₂)= 0
ΔHr= (10 x (-242 KJ) + 8 x (-393.5 KJ)) - (2 x (-125 KJ) + 13 x 0)
ΔHr= -2420 KJ - 3148 KJ + 250 KJ
ΔHr= 5318 KJ