dijaflame67
15.04.2021 •
Chemistry
Hydrochloric acid can be prepared using the reaction described by the chemical equation: 2 NaCl(s) + H2SO4(l) > 2 HCl(g) + Na2 SO4(s). How many grams of HCl can be prepared from 393 g of H2SO4 and 4.00 moles of NaCl?
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Ответ:
145.84 g
Explanation:
2 NaCl(s) + H₂SO₄(l) → 2 HCl(g) + Na₂SO₄(s)To answer this problem first we need to determine the limiting reactant, to do so we convert 393 g of H₂SO₄ into moles using its molar mass:
393 g H₂SO₄ ÷ 98 g/mol = 4.01 mol4.01 moles of H₂SO₄ would react completely with (4.01 * 2) 8.02 moles of NaCl. There are not as many NaCl moles, so NaCl is the limiting reactant.
Now we calculate how many HCl moles are formed, using the number of moles of the limiting reactant and the stoichiometric coefficients of the reaction:
4.00 mol NaCl * = 4.00 mol HClFinally we convert HCl moles into grams, using its molar mass:
4.00 mol HCl * 36.46 g/mol = 145.84 gОтвет:
1. Emitted
2. Absorbed
3. Absorbed
4. Emitted
Explanation:
When an electron jumps to a level of higher energy there's energy absorption.When an electron jumps to a level of lower energy there's energy emission.The higher the n number, the higher the energy level.With the above information in mind, it's just a matter of seeing if the initial n is higher or lower than the final n.