If 1.1 grams of HBr are reacted with 2.1 grams of Mg(OH),, what is the limiting reactant if the goal is to make MgBr2? What mass of MgBr2 is
produced by the limiting reactant?

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Ответ:

okitsfrizz2370

10.06.2020

Chemistry

Explanation:

The given data is as follows.

Density of vinegar = 1.0 g/ml

Specific heat capacity = 4.25 $J/g ^{o}C$

$T_{1}$ = $17 ^{o}C$ , and $T_{2}$ = $14 ^{o}C$

Relation between enthalpy and specific heat is as follows.

$\Delta H = mC \Delta T$

Hence, putting the values into the above formula as follows.

$\Delta H = mC \Delta T$

= $25 \times 1.0 \times 4.25 J/g ^{o}C \times -3^{o}C$ (as density = $\frac{mass}{volume}$ )

= - 315 J

Thus, we can conclude that the enthalpy of reaction is -315 J.

As the value is negative so, it means that heat is releasing. Hence, the reaction is exothermic in nature.

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If 1.1 grams of HBr are reacted with 2.1 grams of Mg(OH),, what is the limiting reactant if the goal is to make MgBr2? What mass of MgBr2 is produced by the limiting reactant?