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choiboiqg2187
25.09.2019 •
Chemistry
If 200 g of benzoyl peroxide are used with 38 kg of ptfe monomer, calculate the expected molecular weight of the polymer if (i) all the termination occurs by combination (ii) all the termination occurs by disproportionation. assume 15% efficiency for the initiator.
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Ответ:
Explanation:
The molecular weight of benzoyl peroxide is 242.23 g/mol.
Therefore, number of moles present in 200 g of benzoyl peroxide are as follows.
No. of moles =![\frac{mass}{\text{molar mass}}](/tpl/images/0260/1085/cf387.png)
=![\frac{200 g}{242.23 g/mol}](/tpl/images/0260/1085/43982.png)
= 0.825 mol
Molecular weight of PTFE is 100 g/mol.Hence, calculate the number of moles of PTFE in 38 kg as follows.
As 1 kg = 1000 g. So, 38 kg = 38000 g.
No. of moles =![\frac{mass}{\text{molar mass}}](/tpl/images/0260/1085/cf387.png)
=![\frac{38000 g}{100 g/mol}](/tpl/images/0260/1085/22808.png)
= 380 mol
As it is given that the initiator is 15% active. So, actual number of moles of benzoyl peroxide are as follows.
= 0.124 mol
For combination, 1 mol of benzoyl peroxide produces 1 chain. Therefore, degree of polymerization will be calculated as follows.
DP =
= 3065.33 mol
Average molecular weight of monomer is as follows.
= 100.05 g/mol
Therefore, calculate the expected molecular weight of polymer as follows.
= 306675.23 g/mol
Hence, for disproportion 1 mole benzoyl peroxide produces 2 chains.
DP =![\frac{2 \times 380}{0.124}](/tpl/images/0260/1085/19f5a.png)
= 6129.03
Therefore, calculate the expected polymer weight as follows.
= 613209.68 g/mol
Thus, we can conclude that the the expected polymer weight is 613209.68 g/mol.
Ответ:
Step-by-step explanation:
f(4) = 42 + 5 =21, f(-10) = (-10)2 +5 = 105 or alternatively f: x → x2 + 5.
The phrase "y is a function of x" means that the value of y depends upon the value of x, so:
y can be written in terms of x (e.g. y = 3x ).
If f(x) = 3x, and y is a function of x (i.e. y = f(x) ), then the value of y when x is 4 is f(4), which is found by replacing x"s by 4"s .
If f(x) = 3x + 4, find f(5) and f(x + 1).
f(5) = 3(5) + 4 = 19
f(x + 1) = 3(x + 1) + 4 = 3x + 7