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carleenespriu
14.07.2019 •
Chemistry
If 25.16 g of chlorine react with 12.99 g of manganese metal, what is the empirical formula of the compound?
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Ответ:
We use the given masses of the reactants to calculate the moles of Mn and Cl. Empirical formula represents the simplest mole ratio of atoms present in a compound.
Moles of Mn =![12.99 g Mn * \frac{1 mol Mn}{54.94 g Mn} = 0.236 mol Mn](/tpl/images/0086/7912/7596f.png)
Moles of Cl =
= 0.710 mol Cl
Simplest mole ratio:![Mn_{\frac{0.236}{0.236}}Cl_{\frac{0.710}{0.236}}](/tpl/images/0086/7912/838a7.png)
So the empirical formula is![MnCl_{3}](/tpl/images/0086/7912/7a838.png)
Ответ:
moderate negative correlation on edge
Step-by-step explanation: