Chemistry: If it takes 38.70 cm^3 of 1.90M NaOH to neutralize 10.30cm^3 of H2SO4 in a battery. What is the concentration of the H2SO4?

If it takes 38.70 cm^3 of 1.90M NaOH to neutralize - id3870319012103853, bobby237065

Ответ:

Isaiahtate053

21.04.2021

Chemistry

3.57 M

Explanation:

The reaction that takes place is:

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

First we calculate how many NaOH moles reacted, using the given concentration and volume:

38.70 cm³ = 38.70 mL1.90 M * 38.70 mL = 73.53 mmol NaOH

Then we convert NaOH moles into H₂SO₄ moles, using the stoichiometric coefficients:

73.53 mmol NaOH * $\frac{1mmolH_2SO_4}{2mmolNaOH}$ = 36.765 mmol H₂SO₄

Finally we calculate the concentration of H₂SO₄:

36.765 mmol H₂SO₄ / 10.30 mL = 3.57 M

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Ответ:

asheeee58

20.04.2022

Chemistry

I'm not sure, however if you put sugar in water then the sugar particles speed up due to the fact that they dissolve in the water. Hope this helped! : D

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If it takes 38.70 cm^3 of 1.90M NaOH to neutralize 10.30cm^3 of H2SO4 in a battery. What is the concentration of the H2SO4?

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