If the rate constant for a reaction triples when the temperature rises from 300. K to 310. K, what is the activation energy of the reaction
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Ответ:
Explanation:
Hello,
In this case, temperature-variable version of the Arrhenius equation is applied in order to compute the activation energy as shown below:
Thus, we replace each variable considering k2=3*k1 (tripling):
Best regards.
Ответ: