In an atom, an electron is confined to a space of roughly 10−10 meters. if we take this to be the uncertainty in the electron's position, what is the minimum uncertainty δp in its momentum? express your answer in kilogram meters per second to two significant figures.

Δp = 3.31 × 10⁻²⁴ kg.m/s

Explanation:

Given:

Electron is confined to a space of,  Δx  = 10⁻¹⁰ m

According to the Heisenberg uncertainty principle, we have

where, h is the plank's constant = 6.626 × 10⁻³⁴ J.s

Δp is the uncertainty in the momentum

on substituting the respective values, we get

or

Δp = 3.31 × 10⁻²⁴ kg.m/s

Explanation:

Let's break it down:

We can now draw the structure of  2,2-dimethyl butane using the following steps: