In one roasting unit, 1000 kg of an ore concentrate of the composition given below is roasted using excess air ni3s 21% fes 40% sio2 31% h20 8% the roasting unit is heated by oil of composition 85% cand 15% h, the amount of oil is 6.2 % of the weight of the ore. the gases from combustion and roasting mix together and are carried through as flue gases s is converted to so2 the roasted product consists of nio, fe: o, and sio2 and the roasting reactions are given as; ni3s27/2023nio 250 2 2fes2 11/202 fe2o3 4s0 (i) explain how you would increase the kinetics of roasting and hence the production rate (5 marks) (i) calculate: a) weight of roasted product (10 marks) volume of the fuel oil given that its density is 0.89 g/cm2 (5 marks) b) volume of so2 in m2 (5 marks) c) (note: atomic weights are ni 59, fe 56, s 32, o= 16, h - 1 )
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Ответ:
Answer and Explanation:
Given the following chemical equation:
Cl₂(g) + F₂(g) ⇒ 2ClF(g)
The coefficients are: 1 for Cl₂, 1 for F₂ and 2 for ClF. The coefficients indicate the number of units of each ompound that participates in the reaction. It gives the proportion of reactants and products in the reaction. These units can be molecules or moles. In this reaction, we can say:
On the particulate level: 1 molecule of Cl₂(g) reacts with 1 molecule of F₂(g) to form 2 molecules of ClF(g).
On the molar level: 1 mol of Cl₂(g) reacts with 1 mol of F₂(g) to form 2 mol of ClF(g).